Q1. Ramesh's age after 15 years will be 5 times his age 5 years back. What is the current age of Ramesh?
A. 15 years
B. 14 years
C. 10 years
D. 7 years
Answer- Option C
Explanation-
Let Ramesh's current age be x Ramesh's age 5 years back = (x - 5) Ramesh's age after 15 years = (x + 15) => x + 15 = 5(x - 5) On solving this, we get x = 10 So, current age of Ramesh = 10 years
Q2. The difference between the ages of two friends is 16 years. If 6 years ago, the elder one was 3 times as old as, the younger one, find their present ages?
A. 10 years and 35 years
B. 12 years and 40 years
C. 15 years and 45 years
D. 14 years and 30 years
Answer- Option D
Explanation-
Let the age of younger friend be x years. Then, age of elder friend = (x + 16)years. x + 16 - 6 = 3(x - 6) => x = 14 Their present ages are 14 years and 30 years
Q3. The product of the ages of Piyush and Bhavana is 240. On multiplying Bhavana's age by two exceeds Piyush's age by 4 years, then what is Bhavana's age?
A. 12 years
B. 20 years
C. 5 years
D. 15 years
Answer- Option A
Explanation-
Let Piyush's age will be x years. Then, Bhavana age will be =
240 x
years According to the question, 2
240 ––– x
= x + 4 => x2 + 4x - 480 = 0 => x = 20 Bhavana's age =
240 20
years = 12 years
Q4. The current age of a mother is 3 years more than three times the age of her daughter. Three years after, mother's age will be 10 years more than twice the age of the daughter. What is the present age of the mother?
A. 35 years
B. 33 years
C. 34 years
D. 32 years
Answer- Option B
Explanation-
Let daughter's age be x Then, mother's age is 3x + 3 3x + 3 + 3 = 2(x + 3) + 10 => x = 10 Hence, mother's age is 3*10 + 3 = 33 years
Q5. 8 years ago, Father was 4 times as old as his son. 8 years hence, Father will be twice as old as his son. What are their current ages?
A. 16 years and 40 years
B. 20 years and 45 years
C. 25 years and 50 years
D. 30 years and 55 years
Answer- Option A
Explanation-
Let son's age 8 years ago be x years. Then, father's age 8 years ago = 4x After 8 years, son's age = x + 8 + 8 = x + 16 Father's age = 4x + 8 + 8 = 4x + 16 4x + 16 = 2(x + 16) => x = 8 Son's present age = x + 8 = 16 years Father's present age = 4x + 8 = 40 years
Q6. The ratio of Ankit's and Neha's age one year ago was 6 : 7 respectively. Four years hence, this ratio would become 7 : 8. How old is Neha?
A. 30 years
B. 34 years
C. 36 years
D. 32 years
Answer- Option C
Explanation-
Let Ankit's age and Neha's age 1 year age be 6x and 7x respectively. After 4 years, Ankit's age = 6x + 1 + 4 = 6x + 5 Similarly, Neha's age = 7x + 1 + 4 = 7x + 5
6x + 5 7x + 5
=
7 8
=> 48x + 40 = 49x + 35 => x = 5 Hence, Neha's age is 7x + 1 = 7*5 + 1 = 36 years
Q7. Mayank's age after six years will be three-seventh of his uncle's age. Ten years ago, the ratio of their ages was 1: 5. What is Mayank's uncle's age at present?
A. 50 years
B. 45 years
C. 40 year
D. 43 years
Answer- Option A
Explanation-
Let the ages of Mayank and his Uncle 10 years ago be x and 5x respectively. After 6 years, Mayank's age = x + 10 + 6 = x + 16 Similarly, Uncle's age = 5x + 10 + 6 = 5x + 16
x + 16 =
3 7
(5x + 16)
=> 7x + 112 = 15x + 48 => x = 8 So, Mayank's Uncle's age is 5*8 + 10 = 50 years
x + 16 - 6 = 3(x - 6)
